RE: ACL question

From: Wade Edwards (wade.edwards@xxxxxxxxxxxxxxxxxxx)
Date: Wed Feb 13 2002 - 18:30:08 GMT-3


   
access-list 1 permit 192.168.123.0 0.0.0.255 ! This will take care of
123
access-list 1 permit 192.168.124.0 0.0.3.255 ! This will take care of
124-127
Everything else will be denied including 128 and 129.

You cannot do it with one access-list line.

HTH L8r.

 -----Original Message-----
From: Sam.MicroGate@usa.telekom.de
[mailto:Sam.MicroGate@usa.telekom.de]
Sent: Wednesday, February 13, 2002 3:02 PM
To: ccielab@groupstudy.com
Subject: ACL question

Suppose that the backbone is advertising the following routes:
192.168.123.0/24
 192.168.124.0/24
192.168.125.0/24
 192.168.126.0/24
 192.168.127.0/24
 192.168.128.0/24
192.168.129.0/24
 I need to filter .128 and .129 and pass every thing else. which of the
following access list is correct
access-list 1 permit 192.168.123.0 0.0.7.255 or
 access-list 2 permit 192.168.124.0 0.0.7.255 or
access-list 3 permit 192.168.125.0 0.0.7.255 or
 access-list 4 permit 192.168.126.0 0.0.7.255 or
 access-list 5 permit 192.168.127.0 0.0.7.255



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