From: fningham@xxxxxxx
Date: Thu Jun 27 2002 - 21:50:24 GMT-3
   
Emmanuel:  What you have shouldn't do anything.  There
are some fundamental
 errors if I understand your description correctly:
   First, if you have r1 and r2 as dlsw peers, i.e., no
border peer, then on r1
 you want the filter applied to the dlsw prom-peer
defaults command not the dlsw
 peer-on-demand-defaults.  You would only use the
prom-peer command when you have
 a border and r1 and r2 are not configured as peers.
For your configuration to
 work as shown you would have a remote-peer statement on
r2 pointing to r1.
    Second, you have converted a non-canonical address
to a canonical address.
 The token-ring address is already in non-canonical
format and should not be
 changed.  (As an aside, the MAC address you are using
belongs to one of the PC's
 in the NMC course).
 Cheers, Fred
 >
 > From: "Emmanuel Oppong" <e-oppong@attbi.com>
 > Date: 2002/06/27 Thu PM 05:01:01 EDT
 > To: <ccielab@groupstudy.com>
 > Subject: Bitswapping and Mac Filtering
 >
 > Guys/gals
 >
 > I need your help on this one:
 >
 > r1 and r2 are configured as dlsw peers.  r1 has a
host on e0 network.  r2
 > has host-1 and host-2
 > on its to0 network.  I want r1's host to communicate
with only host-1 on r2.
 > MAC addresses for
 > the hosts area :
 >
 > r1 host = 0000-8616-3F04
 > r2 host-1 = 0000-F669-5EE7
 > r2 host-2 = 0000-F669-5F25
 >
 > My relevant config for r1 are:
 >
 > r1:
 > dlsw local-peer peer-id 172.16.101.1 promiscuous
 > dlsw peer-on-demand-defaults dmac-output-list 700
 > dlsw bridge-group 1
 > !
 > access-list 700 permit 0000.6F96.7AE7 0000.0000.0000
 > !
 > int e0
 > bridge-group 1
 > !
 > bridge 1 protocol ieee
 > !
 >
 > My questions are:
 > I have bitswapped the mac address of host-1 in the
access-list. Is that the
 > right thing to do,
 > convert r2 host-1 from non-canonical to canonical?
Even if it is right, how
 > does r1 associate
 > these 2 mac addresses?  I am thinking that r1
receives a frame from r2 with
 > host-1 source mac address
 > in the noncanonical form, right?  But how does r1
know that the canonical
 > form in the access-list
 > matches the host-1 source mac address coming from r2?
 Can someone explain
 > this?
 >
 > What is the right way to configure thsi scenario?
 >
 > Thanks.
 >
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