From: Mohammed Shameen Abdul Jabbar (ccie.xpert@gmail.com)
Date: Wed Apr 19 2006 - 06:30:08 GMT-3
Hi,
I have a question on the frame-relay traffic shapping.
If in the question, it is mentioned that the port speed of s0/0 is 512K &
DLCI 204 uses 128k, The remaining two DLCI's 201 and 203 share the "
remaining-bandwidth".
I am confused on the term "remaining-bandwidth" . I have read that , only
75% of the port banwidth is used for normal traffic.
So the remaining bandwith should be calculated as :
512 x 75/100 = 384kbps
DLCI 204 =
128kbps
DLCI 201 = DLCI 203 =
(384 - 128)/2 = 256/2 = 128kbps
OR is it calculated as
DLCI 204 = 128Kbps
DLCI 201 = DLCI 203 =
(512 - 128)/2 = 192Kbps
Can anyone tell me which one is the correct method.
Regards
shamin
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