From: Scott Morris (swm@emanon.com)
Date: Wed Jan 17 2007 - 09:26:37 ART
Your variables:
5 00000101
10 00001010
13 00001101
14 00001110
By themselves it looks ugly since 4 bits are varied between them all. Start
pairing:
5 00000101
13 00001101
Now there's only 1 bit different there (mask of .8 in this octet)
10 00001010
14 00001110
Same thing here. One bit different, happens to be in the .4 position.
Divide and conquer. And this is why notepad is your friend, 'cause cutting
and pasting makes the visual comparison much easier!
HTH,
Scott Morris, CCIE4 (R&S/ISP-Dial/Security/Service Provider) #4713, JNCIE
#153, CISSP, et al.
CCSI/JNCI-M/JNCI-J
IPexpert VP - Curriculum Development
IPexpert Sr. Technical Instructor
smorris@ipexpert.com
http://www.ipexpert.com
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Salman Abbas
Sent: Wednesday, January 17, 2007 5:35 AM
To: Cisco certification
Subject: Complex Access-list
Hi GS,
Can you pls help me to use one or at the most two access-list lines to allow
only the following networks:
1.1.5.0
1.1.10.0
1.1.13.0
1.1.14.0
Thanks in advance,
Regards,
Salman
This archive was generated by hypermail 2.1.4 : Thu Feb 08 2007 - 23:46:56 ART