Re: IPV6 Question

From: shiran guez (shiranp3@gmail.com)
Date: Thu Oct 25 2007 - 03:45:48 ART


The easyest way for this 2 network summary is to take the bit format

remember :

1) IPv6 is represented in Hex
2) each part contain 16 bit

So you have here contigues 3 parts so you have 3x16 = 48
now take the 4th part and convert it to bin

12
0000 0000 0001 0010
25
0000 0000 0010 0101

now you can see very clear how many bit you can take to the summary, 10 bit

now take the first 48 bits + the 10 from your summary and you got a /58

Realy not very hard just a lot of 0 and 1.

On 10/24/07, Martin McGannon <mmcgannon@pmis.ie> wrote:
>
> Hi,
>
> A few basic questions :-
>
>
> If requested to summarize the following prefixes in IPV6 what would the
> summary address be
>
> 2001:141:1:12/64
> 2001:141:1:25/64
>
> 2001:141:1::/58 or 59? and why.
>
> Also in a prevoius lab exexcise I was asked to implement Site Local
> Addressing
> with my existing IPV4 address in place. The interface address was
> 192.168.1.100 say. How would I create a Site Local address from this, give
> that the first 10 bits are always FEC0:X:X etc.. Any ideas.
>
> Lastly with RIPNG over NBMA do we need to add the broadcast keyword for
> the
> link locals. Can we use neighbor statements under the Router Process.
>
> Many Thanks,
>
> Martin
>
> _______________________________________________________________________
> Subscription information may be found at:
> http://www.groupstudy.com/list/CCIELab.html
>

-- 
Shiran Guez
MCSE CCNP NCE1
http://cciep3.blogspot.com
http://www.linkedin.com/in/cciep3


This archive was generated by hypermail 2.1.4 : Fri Nov 16 2007 - 13:11:18 ART