From: Marvin Greenlee (mgreenlee@ipexpert.com)
Date: Thu Jul 10 2008 - 14:45:25 ART
Look at the binary for the bits. 7 of the bits are the same for each pair.
5 - 00000101
13 00001101
10 - 00001010
14 - 00001110
There is a difference between a subnet mask and a wildcard mask. 0.0.4.255
and 0.0.8.255 are wildcard masks, only stating which bits to match.
Marvin Greenlee, CCIE #12237 (R&S, SP, Sec)
Senior Technical Instructor - IPexpert, Inc.
Telephone: +1.810.326.1444
Fax: +1.810.454.0130
Mailto: mgreenlee@ipexpert.com
Progress or excuses, which one are you making?
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Cisco Champ
Sent: Thursday, July 10, 2008 1:32 PM
To: ccielab@groupstudy.com
Subject: simple query on ACL
Hi:
In one of the question requirement was to match (192.168.5.0, 10.0, 13.0 and
14.0) network. Solution is given below, which is giving the results
correctly.
access-list 1 permit 192.168.10.0 0.0.4.255
access-list 1 permit 192.168.5.0 0.0.8.255
But my question is how can we used '192.168.5.0' as Network address for
subnet
mask 255.255.248.0 it should be 192.168.4.0. But when I do this I didn't get
the required results. Can any one tell me how this one is working.
Thanks in advance!!
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